author Andrew Osmond <>
Tue, 16 Oct 2018 08:45:26 -0400
changeset 447457 ccfa531dea0301244c99db4ff26d5610382487e2
parent 419630 da3c81f986fa63b42a2874b1791eddcdbfbe8424
child 481703 9c5b3c7e1ca2240f765d62466cc917ad778407ef
permissions -rwxr-xr-x
Bug 1504699 - Part 7. Update animated image recycling queue to work well with WebRender. r=tnikkel WebRender takes longer than OMTP to release its hold on the current frame. This is because it is in a separate process and holds onto the surface in between rendering frames, rather than getting a reference for each repaint. This patch makes us less aggressive about taking the most recent surface placed in the recycling queue out to avoid blocking on waiting for the surface to be released. Differential Revision:

#!/usr/bin/env python
# This Source Code Form is subject to the terms of the Mozilla Public
# License, v. 2.0. If a copy of the MPL was not distributed with this
# file, You can obtain one at

#   Checks that FILES contains exactly COUNT matches of SEARCH_TERM. If it does
#   not, an error message is printed, quoting ERROR_LOCATION, which should
#   probably be the filename and line number of the erroneous call to
from __future__ import print_function
import sys
import re

search_string = sys.argv[1]
expected_count = int(sys.argv[2])
error_location = sys.argv[3]
replacement = sys.argv[4]
files = sys.argv[5:]

details = {}

count = 0
for f in files:
    text = file(f).read()
    match = re.findall(search_string, text)
    if match:
        num = len(match)
        count += num
        details[f] = num

if count == expected_count:
    print("TEST-PASS | {0} | {1}"
          .format(search_string, expected_count))

    print("TEST-UNEXPECTED-FAIL | {0} | "
    if count < expected_count:
        print("There are fewer occurrences of /{0}/ than expected. "
              "This may mean that you have removed some, but forgotten to "
              "account for it {1}.".format(search_string, error_location))
        print("There are more occurrences of /{0}/ than expected. We're trying "
              "to prevent an increase in the number of {1}'s, using {2} if "
              "possible. If it is unavoidable, you should update the expected "
              "count {3}.".format(search_string, search_string, replacement,

    print("Expected: {0}; found: {1}".format(expected_count, count))
    for k in sorted(details):
        print("Found {0} occurences in {1}".format(details[k], k))